The potential field depends on the x- and y-coordinates as V = x2-y2. The corresponding electric field lines in xy plane are as

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answer is A.

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Detailed Solution

Ex→=−δVδxi^=−2xi^ Ey→ = δVδy = 2yj^ So E→= -2xi→+2yj^Also electric field lines are perpendicular to equipotential lines .

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