Q.
The potential field of an electric field E→=(yi^+xj^) is
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a
V = -xy + constant
b
V = -(x + y) + constant
c
V = -(x2 +/)+constant
d
V = constant
answer is A.
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Detailed Solution
dV=-E→·dr→ =-(yi^+xj^)·(dxi^+dyj^) =-(y d x+x d y)=-d(x y)Integrating, we get V = -.xy+constant