Q.

The potential field of an electric field E→=(yi^+xj^) is

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a

V = -xy + constant

b

V = -(x + y) + constant

c

V = -(x2 +/)+constant

d

V = constant

answer is A.

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Detailed Solution

dV=-E→·dr→ =-(yi^+xj^)·(dxi^+dyj^) =-(y d x+x d y)=-d(x y)Integrating, we get V = -.xy+constant
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The potential field of an electric field E→=(yi^+xj^) is