The potential at a point x (measured in μm) due to some charges situated on the x-axis is given by V(x)=20/x2−4volt.The electric field E at x = 4 μm is given by:
5/3 volt/μm and in the +ve x direction.
10/9 volt/μm and in the -ve x direction.
10/9 volt/μm and in the +ve x direction.
5/3 volt/μm and in the -ve x direction.
E=−dVdx=−20ddx1x2−4=-−40xx2−42=+40×4(16−4)2=+109