Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The potential at a point x (measured in μm ) due to some charges situated on the x-axis is given by V(x)=20/(x2−4) Volts. The electric field E at x=4 μm  is given by

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

5/3 Volt/ μm  and in the –ve x direction

b

5/3 Volt/ μm  and in the +ve x direction

c

10/9 Volt/ μm  and in the –ve x direction

d

10/9 Volt/ μm  and in the +ve x direction.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Vx=20x2−4 E=-dVdx=20(x2−4)2(2x−0)=160144=109
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon