In a potentio meter experiment, the balancing length with a cell is at a length of 240 cm. On shunting the cell with a resistance of 2 Ω, the balancing length becomes 120cm. The internal resistance of the cell is:

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4 Ω

2 Ω

1 Ω

0.5 Ω

answer is B.

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Detailed Solution

r=RL1−L2L2=2120120=2Ω

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