In a potentiometer arrangement, a cell of emf $$1.20$$ V gives a balance point at $$30$$ cm length of the wire. This cell is now replaced by another cell of unknown emf. It the ratio of the emf’s of two cells $$is1.5$$ , the difference in the balancing length of the potentiometer wire in the two cases is

Question

In  a potentiometer arrangement, a cell of emf $$1.20$$ V     gives a balance point at $$30$$ cm     length of the wire. This cell is now replaced by another  cell of unknown emf. It the ratio of the emf’s of two cells $$is1.5$$     , the difference in the balancing length of the  potentiometer wire in the two cases is

Infinity Learn · Accepted Answer

Balancing  length $$l1=30$$ cm       Ratio  of emfs of two sells $$E1E2=1.5$$     $$E1E2=l1l2$$      ⇒$$1.5=30l2$$            $$l2=20$$ cm     Difference  in the balancing length $$=$$ $$l1$$−$$l2=30$$−$$20=10$$ cm     .

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In a potentiometer arrangement, a cell of emf 1.20 V gives a balance point at 30 cm length of the wire. This cell is now replaced by another cell of unknown emf. It the ratio of the emf’s of two cells is1.5 , the difference in the balancing length of the potentiometer wire in the two cases is

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