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Q.

In a potentiometer balancing length of a 10 volt cell is 60 cm. Now the wire of the potentiometer is replaced by a new wire of same material but having length twice the original length and radius half the original radius. Then the balancing length of 10 volt cell will be.

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a

30 cm

b

240 cm

c

95 cm

d

120 cm

answer is D.

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Detailed Solution

If Eo be the emf of primary driving cell of potentiometer, and λ be the resistance per unit length of potentiometer wire, thenE=Eo(λL)(lλ)=EolL For the new wire, E=Eo.l'2L ∴ Eol'2L=Eol2⇒l'=2l=2×60 cm=120 cm.

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