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The potentiometer consists of a wire of length $4 m$ and resistance $10 Ω .$ It is connected to a cell of emf $2V,$ the potential difference per unit length of the wire will be :

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10 V/m

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detailed solution

Correct option is D

Resistance R=10 Ω Length l=4 m emf of a cell E=2V i=ER=210=0.2 A Therefore, potential difference per unit length of the wire is given by=iRl=0.2×104=0.5 V/m

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The potentiometer consists of a wire of length 4 m and resistance 10 Ω. It is connected to a cell of emf 2V, the potential difference per unit length of the wire will be :

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The potentiometer consists of a wire of length $4 m$ and resistance $10 Ω .$ It is connected to a cell of emf $2V,$ the potential difference per unit length of the wire will be :