In a potentiometer experiment, the balance with a cell is at length 240 cm. On shunting the cell with a resistance of 2Ω, the balancing length becomes 120 cm. The internal resistance of the cell is.

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0.5 Ω

1 Ω

2 Ω

4 Ω

answer is C.

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Detailed Solution

The internal resistance r is given byr=Rl−l′l′=2240−120120=2×120120=2Ω

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