First slide

potentiometer

Question

In a potentiometer experiment, the balance with a cell is at length 240 cm. On shunting the cell with a resistance of 2 $Ω$ , the balancing length becomes 120 cm. The internal resistance of the cell is.

Easy

A

0.5 $Ω$
B

1 $Ω$
C

2 $Ω$
D

4 $Ω$

Solution

The internal resistance r is given by
$\begin{aligned} r = R [\frac{l - l^{'}}{l^{'}}] = 2 [\frac{240 - 120}{120}] \\ = 2 \times (\frac{120}{120}) = 2 Ω \end{aligned}$

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