First slide

potentiometer

Question

A potentiometer having the potential gradient of 2 mV/cm is used to measure the difference of potential across a resistance of 10 ohm. If a length of 50 cm of the potentiometer wire is required to get the null point, the current passing through the 10 ohm resistor is (in mA)

Easy

A

1
B

2
C

5
D

10

Solution

$\begin{array}{l} V = xl \Rightarrow iR = xl \\ \Rightarrow i \times 10 = (\frac{2 \times 10^{- 3}}{10^{- 2}}) \times 50 \times 10^{- 2} = 0 .1 \\ \Rightarrow i \times 10 \times 10^{- 3} A = 10 mA \end{array}$

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