A potentiometer having the potential gradient of 2 mV/cm is used to measure the difference of potential across a resistance of 10 ohm. If a length of 50 cm of the potentiometer wire is required to get the null point, the current passing through the 10 ohm resistor is (in mA)

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answer is D.

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Detailed Solution

V=xl ⇒ iR =xl⇒ i × 10 = 2 × 10−310−2 × 50 × 10−2 = 0.1⇒ i × 10 × 10−3 A=10 mA

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