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A potentiometer having the potential gradient of 2 mV/cm is used to measure the difference of potential across a resistance of 10 ohm. If a length of 50 cm of the potentiometer wire is required to get the null point, the current passing through the 10 ohm resistor is (in mA)

a
1
b
2
c
5
d
10

detailed solution

Correct option is D

V=xl ⇒  iR =xl⇒   i × 10 = 2 × 10−310−2   × 50 × 10−2  =  0.1⇒   i × 10   × 10−3  A=10  mA

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