Questions
A potentiometer is used for the comparison of e.m.f. of two cells E1 and E2. For cell E1 the no deflection point is obtained at 20 cm and for E2 the no deflection point is obtained at 30 cm. The ratio of their e.m.f.'s will be
detailed solution
Correct option is A
Ratio will be equal to the ratio of no deflection lengths. Hence, E1E2 = l1 l1 = 23Talk to our academic expert!
Similar Questions
An Edison cell and a Iead accumulator when placed in series produce a null deflection at a distance 204 cm in a potentiometer. But when placed in opposition produces null deflection. at a distance of 36 cm. If the e.m.f. of Edison cell is 1 . 4 V, the e.m.f. of lead accumulator is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests