Questions
A potentiometer wire of length
detailed solution
Correct option is B
Potentiometer wire of length L=100 cm Resistance R=5 Ω Cell of emf E=2 V Source of emf E1=5 mV Balancing length l=10 cm E1=(ER+RS) RLl 5×10−3=(25+RS) 5100×10 5×10−3=2×5×10(5+RS)100 ∴RS= 195 ΩTalk to our academic expert!
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