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A potentiometer wire of length 100cm  has a resistance 5ohm . It is connected in series with a resistance and a cell of emf 2V  and of negligible internal resistance. A source of emf 5mV  balanced by 10cm  length of potentiometer wire. The value of external resistance is_____   

a
540 Ω
b
195 Ω
c
190 Ω
d
990 Ω

detailed solution

Correct option is B

Potentiometer wire of length L=100 cm Resistance R=5 Ω Cell of emf E=2 V Source of emf E1=5 mV Balancing length l=10 cm E1=(ER+RS) RLl 5×10−3=(25+RS) 5100×10 5×10−3=2×5×10(5+RS)100 ∴RS= 195 Ω

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