Questions
A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. and a resistance . An unknown e.m.f. E is balanced at a length of the potentiometer wire. The e.m.f. E will be given by
detailed solution
Correct option is D
The current through the potentiometer wire is I=E0r+r1and the potential difference across the wire is V=Ir=E0rr+r1The potential gradient along the potentiometer wire is k=VL=E0rr+r1LAs the unknown e.m.f. E is balanced against length l of the potentiometer wire,∴ E=kl=E0rr+r1lLTalk to our academic expert!
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A cell of resistance and emf 10 volt is connected to a uniform wire of length 500 cm and resistance 3 ohm. The potential gradient in the wire is
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