A pot-maker rotates pot-making wheel of radius 3 m by applying a force of 200 N tangentially; because of this if wheel completes exactly 1½ revolution, the work done by him is
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a
5657.86 J
b
4321.32 J
c
4197.5 J
d
5000 J
answer is A.
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Detailed Solution
work done in rotational motion is τθ here τ= 200 x3 θ= 1,5 x2π