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Q.

Power dissipated in an LCR series circuit connected to an AC source of emf ε is

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a

ε2RR2+Lω−1Cω2

b

ε2R2+Lω−1Cω2R

c

ε2R2+Lω−1Cω2R

d

ε2RR2+Lω−1Cω2

answer is A.

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Detailed Solution

Power dissipated in series LCR circuit,P=Irms2R=εrms2R|Z|2=ε2RR2+ωL−1ωC2
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