Power factor of a L−R series circuit is 0.8. When a capacitor is connected in series with R and L, the power factor increases to unity. Then reactance of the capacitor is

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3R4

2R3

answer is A.

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Detailed Solution

RR2+XL2=0.8⇒XL=3R4Again, RR2+(XL−XC)2=1⇒XC=XL

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