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Q.

The power of a lens having refractive index 1.25  is +3 diapters. When placed in a liquid, its power is −2 diopters. The refractive index of the liquid is

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a

1.2

b

1.4

c

1.5

d

1.6

answer is C.

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Detailed Solution

1f =(μ−1) (1R1 −1R2)=3 3=(1.25−1)(1R1−1R2) ............(1) and   −2=(1.25μ−1) (1R1−1R2) ……………..(2)−32 =0.25μ1.25−μ⇒ −0.5μ =3.75 −3μ            ⇒ μ=3.75/2.5=1.5
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