The power of a motor is 200W. If the unit of length is doubled, that of mass is halved and that of time is also doubled, then the power of the motor in the new system is

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3200 W

800new units

12.5 new units

12.5 W

answer is B.

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Detailed Solution

N1N2=[M2M1][L2L1]2[T2T1]−3 200N2=[M2M][2LL]2[2TT]−3 =200N2=14 N2=800 new units

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