Questions
The power of a motor is 200W. If the unit of length is doubled, that of mass is halved and that of time is also doubled, then the power of the motor in the new system is
detailed solution
Correct option is B
N1N2=[M2M1][L2L1]2[T2T1]−3 200N2=[M2M][2LL]2[2TT]−3 =200N2=14 N2=800 new unitsTalk to our academic expert!
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