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Q.

The power radiated by a black body is P, and it radiates maximum energy around the wavelength λ0. If the temperature of black body is now changed so that it radiates maximum energy around a wavelength 3λ04, the power radiated by it is 64P81×n , then find the value of ‘n’.

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answer is 4.

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Detailed Solution

We know,Power, P=eAσT4∴P∝T4 Wien's Displacement LaW, λmT=b∴T∝1λm Thus, P∝1λm4⇒P1P=λmλm14⇒P1P=λm3λm 44⇒n×64 81=25681 ⇒n=4

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