Questions
The power of a sound from the speaker of a radio is 20 mW. By turning the knob of the volume control, the power of the sound is increased to 400 mW. The power increase in decibels as compared to the original power is
detailed solution
Correct option is A
P∝IL1=10log10I1I0 and L2=10log10I2I0So L2−L1=10log10I2I1=10log10P2P1=10log1040020=10log1020=10log(2×10)=10(0.301+1)=13 dBTalk to our academic expert!
Similar Questions
Two loud speakers are being compared, and one is perceived to be 32 times louder than the other. What will be the difference in intensity levels between the two when measured in decibels?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests