The power of a sound from the speaker of a radio is 20 mW. By turning the knob of the volume control, the power of the sound is increased to 400 mW. The power increase in decibels as compared to the original power is

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13 dB

10 dB

20 dB

800 dB

answer is A.

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Detailed Solution

P∝IL1=10log10I1I0 and L2=10log10I2I0So L2−L1=10log10I2I1=10log10P2P1=10log1040020=10log1020=10log(2×10)=10(0.301+1)=13 dB

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