PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with constant velocity v as shown. The force neededto maintain constant speed of EF is(neglect the weight of conductor)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1vRμ0Iv2πlnba2
b
μ0Iv2πlnba 1vR
c
μ0Iv2πlnba2vR
d
vRμ0Iv2πlnba2
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Induced emf ∫ab Bvdx=∫ab μ0I2πxvdx⇒ Induced emf, E=μ0Iv2πlnba⇒ Power dissipated =E2R Also, power =F⋅v⇒F=E2vRF=μ0Iv2πlnba21vR
PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with constant velocity v as shown. The force neededto maintain constant speed of EF is(neglect the weight of conductor)