First slide

Physical quantities and units

Question

A pressure of $10^{6} d y n e c m^{- 2}$ is equivalent to

Moderate

A

$10^{5} N m^{- 2}$
B

$10^{4} N m^{- 2}$
C

$10^{6} N m^{- 2}$
D

$10^{7} N m^{- 2}$

Solution

1 Newton $= 10^{5}$ dyne and1m=100 cm
$10^{6} d y n e c m^{- 2} = 10^{6} \times 10^{- 5} N \times {(10^{- 2} m)}^{2} = 10^{5} N m^{- 2}$

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