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Q.

The pressure inside a small air bubble of radius 0.1 mm situated just below the surface of water will be equal to [Take surface tension of water  70×10−3Nm−1 and atmospheric pressure = 1.013×105Nm−2 ]

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a

2.054×103Pa

b

1.027×103Pa

c

1.027×105Pa

d

2.054×105Pa

answer is C.

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Detailed Solution

Excess pressure inside the air bubble =2Tr⇒Pin −Pout =2Tr=2×70×10−30.1×10−3=1400Pa⇒Pin =1400+1.013×105=1.027×105Pa
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