Questions
Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is :
detailed solution
Correct option is A
Pressure inside 1st bubble= P0+4 TR1=1.01 ⇒1+4 TR1=1.01 ⇒R1=4T0.01Pressure inside 2nd bubble=P0+4 TR2=1.02 ⇒1+4 TR2=1.02 ⇒R2=4T0.02We know that, volume ∝radius3 ⇒V1 V2=R1R23=0.020.012=81Talk to our academic expert!
Similar Questions
A bubble having surface tension. T and radius R is formed on a ring of radius . Air is blown inside the tube with velocity v as shown. The air molecule collides perpendicularly with the will of the bubble and stops. Calculate the radius at which the bubble separates from the ring
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