Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is

Outside pressure = 1 atmPressure inside first bubble = 1.01 atmPressure inside second bubble = 1.02 atmExcess pressure ΔP1=1.01−1=0.01 atmExcess pressure  ΔP2=1.02−1=0.02 atmΔP∝1r⇒r∝1ΔP⇒r1r2=ΔP2ΔP1=0.020.01=21Since  V=43πr3 ∴V1V2=r1r23=213=81