Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is

Outside pressure = 1 atmPressure inside first bubble = 1.01 atmPressure inside second bubble = 1.02 atmExcess pressure ∆P1 = 1.01-1 = 0.01 atmExcess pressure ∆P2 = 1.02 -1 = 0.02 atm∆P ∞ 1r   ⇒ r = 1∆P ⇒r1r2= ∆P2∆P1 = 0.020.01 = 21Since V = 43πr3      V1V2 = (r1r2)3 = (21)3 = 81