First slide

Introduction-thermodynamics

Question

The pressure and temperature of an ideal gas in a closed vessel are 720 kPa and 40^oC respectively. If $\frac{1}{4}$ th of the gas is released from the vessel and the temperature of the remaining gas is raised to 353^oC, the final pressure of the gas is

Moderate

A

1440 kPa
B

1080 kPa
C

720 kPa
D

540 kPa

Solution

$\begin{array}{l} P_{1} = 720 kpa, T_{1} = 40^{\circ} C = 273 + 40 = 313 K \\ P \propto mT \Rightarrow \frac{P_{2}}{P_{1}} = \frac{m_{2}}{m_{1}} \frac{T_{2}}{T_{1}} = \frac{3}{4} \times \frac{626}{313} = 1 .5 \\ \Rightarrow P_{2} = 1 .5 P_{1} = 1 .5 \times 720 = 1080 kPa \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App