Q.

Pressure versus temperature graph of an ideal gas is as shown in figure.Corresponding density (ρ) versus volume (V) graph will be

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a

b

c

d

answer is B.

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Detailed Solution

Process AB is an isothermal process, i.e., P∝1/V and since ρ∝1/V,ρ−V graph will be a rectangular hyperbola. Pressure is increasing; therefore, volume will increase. Process BC is an isochoric process. Therefore, V = constant and since ρ = m/V, density is also constant, i.e., ρ -V graph is a dot. Process CD is inverse of process AB and process DA is inverse is BC.
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Pressure versus temperature graph of an ideal gas is as shown in figure.Corresponding density (ρ) versus volume (V) graph will be