Pressure versus temperature graph of an ideal gas is as shown in figure.Corresponding density (ρ) versus volume (V) graph will be
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
b
c
d
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Process AB is an isothermal process, i.e., P∝1/V and since ρ∝1/V,ρ−V graph will be a rectangular hyperbola. Pressure is increasing; therefore, volume will increase. Process BC is an isochoric process. Therefore, V = constant and since ρ = m/V, density is also constant, i.e., ρ -V graph is a dot. Process CD is inverse of process AB and process DA is inverse is BC.