First slide

Thermometry

Question

Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point ‘A’ is $d_{0}$ . Density at point ‘B’ will be

Moderate

A

$\frac{3}{4} d_{o}$
B

$\frac{3}{2} d_{o}$
C

$\frac{4}{3} d_{o}$
D

$2 d_{o}$

Solution

PV = nRT = $\frac{m}{M} R T$
$\begin{array}{l} p = \frac{m}{v} \frac{R}{M} T = \frac{d R T}{M} \\ d = \frac{P M}{R T} \\ d_{A} = \frac{P_{o} M}{R T_{o}} \\ d_{B} = \frac{3 P_{o} M}{R 2 T_{o}} = \frac{3}{2} d_{o} \end{array}$

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