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The pressure in a water tap at the base of a building is $3 \times 10^{6} d y n e c m^{- 2}$ and on its top it is $1.6 \times 10^{6} d y n e c m^{- 2}$ and on its top building is approximately

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14 m

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140 m

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detailed solution

Correct option is B

Pbase−Ptop=hρwg ⇒ 3-1.6×106=h(1)(1000)⇒ h=1.4×1061000cm⇒ h=1400 cm⇒ h=14 m

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The pressure in a water tap at the base of a building is 3×106dyne cm−2 and on its top it is 1.6×106dyne cm−2 and on its top building is approximately

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The pressure in a water tap at the base of a building is $3 \times 10^{6} d y n e c m^{- 2}$ and on its top it is $1.6 \times 10^{6} d y n e c m^{- 2}$ and on its top building is approximately