The pressure of water in a water pipe when tap it opened and closed respectively 3×105N/m2 and 3.5×105N/m2. With open tap the velocity of water flowing is :
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a
10 m/s
b
5 m/s
c
20 m/s
d
15 m/s
answer is A.
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Detailed Solution
P1+12ρv12=P2+12ρv22P1−P2=12ρv22Since tap is closed, v1 = 03.5×105−3×105=12×103×v2v=10m/s