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At a pressure of 24 x 105 dyne / cm2 the volume of O2 is 10 lit and mass is 20 gm. The r.m.s velocity will be

a
800 m/s
b
400 m/s
c
600 m/s
d
200 m/s

detailed solution

Correct option is C

Vrms=3RTM    PV=nRT; PV=mMRT ; RTM=PVm M is the molecuar wieight and m is the mass or the gasVrms= 3PVm= 3×24×104×10×10-320×10-3  =600 m/s

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