The pressure (1 X 105Nm-2) of the air filled in a vessel is decreased adiabatically so much as to increase its volume three times. The air pressure is (γ for air = 1.4, log10 3 = 0.4771, log10 2.148= 0.33206)

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2.14 X 104 Nm-2

2.19 x 105 Nm--2

1.14 X 105 Nm-2

3.14 x 104 Nm-2

answer is A.

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Detailed Solution

Using p1V1γ=p2V2γ, we get p2=p1V1V2γ=1×1051314=2.14×104Nm−2

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