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Q.

The pressures of water in a water pipe when the tap is closed and open are respectively 3.5 x 105 N/m2 and 3 x 105 N/m2. The velocity of water flowing through the pipe when the tap is open is:

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a

10 m/s

b

0.5 x 106 m/s

c

3.5×1063×105m/s

d

3×1053.5×106m/s

answer is A.

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Detailed Solution

From Bernoulli's theoremP1+12ρv12=P2+12ρu22 ⇒3.5×105+0=3×105+12×103u22 ⇒               u2=(0.5×105)×2103=10 ms-1
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