A prism (μ=1.5) has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36’ = 0.75)
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a
18∘36′
b
20∘30′
c
18∘
d
22∘1′
answer is A.
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Detailed Solution
For surface AC1μ=sin30∘sine⇒sine=μsin30∘⇒sine=1.5×12=0.75⇒e=sin−1(0.75)=48∘36′ From figure δ=e−30∘ =48∘36′−30∘=18∘36′
A prism (μ=1.5) has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36’ = 0.75)