First slide

Prism

Question

A prism $(μ = 1 .5)$ has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36’ = 0.75)

Moderate

A

$18^{\circ} 36^{'}$
B

$20^{\circ} 30^{'}$
C

$18^{\circ}$
D

$22^{\circ} 1^{'}$

Solution

$For surface AC \frac{1}{μ} = \frac{\sin 30^{\circ}}{sine} \Rightarrow sine = μsin 30^{\circ}$
$\Rightarrow sine = 1 .5 \times \frac{1}{2} = 0 .75$
$\Rightarrow e = \sin^{- 1} (0.75) = 48^{\circ} 36^{'}$
$From figure δ = e - 30^{\circ} = 48^{\circ} 36^{'} - 30^{\circ} = 18^{\circ} 36^{'}$

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