Questions
A prism (µ: 1.5) has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36' = 0.75)
detailed solution
Correct option is A
For surface AC1μ=sin30osin e⇒sin e=μsin300⇒sin e=1.5×12=0.75⇒e=sin−10.75=48o36'From figure δ=e−30o=48o36'−30o=18o36'Talk to our academic expert!
Similar Questions
ABC is an isosceles right angled triangle with the angle BAC 90o. A ray of light parallel to the base BC strikes the face AB. The refracted ray in the prism strikes the base BC. If the refractive index of the material of the prism is , find the total angle of deviation of the final emergent ray
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