A prism (µ: 1.5) has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36' = 0.75)
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a
18° 36'
b
20° 30'
c
18°
d
22° 1'
answer is A.
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Detailed Solution
For surface AC1μ=sin30osin e⇒sin e=μsin300⇒sin e=1.5×12=0.75⇒e=sin−10.75=48o36'From figure δ=e−30o=48o36'−30o=18o36'
A prism (µ: 1.5) has the refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36' = 0.75)