For a prism kept in air, it is found that for an angle of incidence $$60$$°, the angle of refraction 'A', angle of deviation ' δ' and angle of emergence 'e' become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is

Question

For a prism kept in air, it is found that for an angle of incidence $$60$$°, the angle of refraction 'A', angle of deviation ' δ' and angle of emergence 'e' become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is

Infinity Learn · Accepted Answer

Given i $$=$$ $$60$$°, A $$=$$ δ$$=$$ eδ $$=$$ i $$+e$$ $$-$$ A ⇒ δ $$=$$ $$i($$∵ e $$=$$ $$A)$$ and δ $$=$$ i $$=$$ eμ$$=sinA+$$δ$$m2sinA2Here$$, angle of deviation is minimum $$($$∵ i $$=$$ $$e)$$μ$$=sin60$$°$$+60$$°$$2sin60$$°$$/2=3$$

For a prism kept in air, it is found that for an angle of incidence $60 °$ , the angle of refraction ' $A$ ', angle of deviation ' $δ$ ' and angle of emergence 'e' become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is

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For a prism kept in air, it is found that for an angle of incidence 60°, the angle of refraction 'A', angle of deviation ' δ' and angle of emergence 'e' become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

For a prism kept in air, it is found that for an angle of incidence $60 °$ , the angle of refraction ' $A$ ', angle of deviation ' $δ$ ' and angle of emergence 'e' become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is