First slide

Prism

Question

A prism of refracting angle 60° is made with a material of refractive index $μ$ . For a certain wavelength of light, the angle of minimum deviation is 30°. For this, wavelength the value of refractive index of the material is

Moderate

A

1.231
B

1.820
C

1.503
D

1.414

Solution

$μ = \frac{\sin (\frac{A + δ_{m}}{2})}{\sin (\frac{A}{2})} = \frac{\sin (\frac{60^{\circ} + 30^{\circ}}{2})}{\sin \frac{60^{\circ}}{2}} = \frac{\sin 45^{\circ}}{\sin 30^{\circ}} = 1 .414$

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