Questions
For a prism of refractive index 1.732, the angle of minimum deviation is equal to the angle of the prism. The angle of-the prism is
detailed solution
Correct option is C
μ=sinA+δm2sinA2=sinA+A2sinA2=sinAsinA2=2sinA2cosA2sinA2=2cosA2So, 3=2cosA2⇒32=cosA2⇒A=60oTalk to our academic expert!
Similar Questions
ABC is an isosceles right angled triangle with the angle BAC 90o. A ray of light parallel to the base BC strikes the face AB. The refracted ray in the prism strikes the base BC. If the refractive index of the material of the prism is , find the total angle of deviation of the final emergent ray
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