A prism of refractive index μ and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in terms of μ is
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a
sin−1μ2
b
sin−1μ−12
c
2cos−1μ2
d
cos−1μ2
answer is C.
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Detailed Solution
Given δm=A, as μ=sinA+δm2sinA2 ⇒μ=sinA+A2sinA2=2cosA2⇒A=2cos−1μ2