First slide

Prism

Question

A prism of refractive index $\sqrt{2}$ has a refracting angle of 60°. At what angle a ray must be incident on it so that it suffers a minimum deviation

Moderate

A

45°
B

60°
C

90°
D

180°

Solution

$μ = \frac{\sin i}{\sin \frac{A}{2}} \Rightarrow \sqrt{2} = \frac{\sin i}{\sin (\frac{60}{2})} \Rightarrow i = 45^{\circ}$

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