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In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process the temperature of the gas is increased by ΔT . The amount of heat absorbed by gas is (R is gas constant) :

a
12RΔT
b
32RΔT
c
12KRΔT
d
RΔT

detailed solution

Correct option is A

VT = K⇒V(PVnR)=k⇒PV2=K ∵C=R1−x+CV (for polytropic process)C=R1−2+3R2=R2 ∴ΔQ=nC  ΔT =R2×ΔT

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