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Q.

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process the temperature of the gas is increased by ΔT . The amount of heat absorbed by gas is (R is gas constant) :

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a

12RΔT

b

32RΔT

c

12KRΔT

d

RΔT

answer is A.

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Detailed Solution

VT = K⇒V(PVnR)=k⇒PV2=K ∵C=R1−x+CV (for polytropic process)C=R1−2+3R2=R2 ∴ΔQ=nC  ΔT =R2×ΔT
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