Questions
On producing the waves of frequency 1000 Hz in a Kundt's tube, the total distance between 6 successive nodes is 85 cm. Speed of sound in the gas filled in the tube is
detailed solution
Correct option is B
Distance between six successive node=5λ2=85cm⇒λ=2×855=34 cm=0.34 mTherefore, speed of sound in gas =nλ=1000×0.34=340 m/sTalk to our academic expert!
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A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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