First slide

Stationary waves

Question

On producing the waves of frequency 1000 Hz in a Kundt's tube, the total distance between 6 successive nodes is 85 cm. Speed of sound in the gas filled in the tube is

Moderate

A

330 m/s
B

340 m/s
C

350 m/s
D

300 m/s

Solution

Distance between six successive node
$= \frac{5 λ}{2} = 85 cm \Rightarrow λ = \frac{2 \times 85}{5} = 34 cm = 0 .34 m$
Therefore, speed of sound in gas
$= nλ = 1000 \times 0 .34 = 340 m / s$

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