Question

A professional diver of mass 60 kg performs a dive from a platform 10 m above the water surface. Find the magnitude of the average impact force experienced by him if the impact time is 1s on collision with water surface. Assume that the velocity of the diver just after entering the water surface is 4ms^-1 .

Moderate

Solution

$F = \frac{dp}{dt} = \frac{m (v - u)}{t} = 60 (\frac{14 - 4}{1}) = 600 N u = \sqrt{2 gh} = \sqrt{2 \times 9.8 \times 10} = 14 m / s$

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