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Q.

A projectile can have same range from two angles of  projection with same initial speed. If h1 and h2 be the maximum heights, then

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a

R=h1h2

b

R=2h1h2

c

R=2h1h2

d

R=4h1h2

answer is D.

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Detailed Solution

R=u2sinθg at angles θ and 90°-θNow,    h1=u2sin2θ2g and h2=u2sin290°-θ2g=u2cos2θ2gh1h2=u2sin2θg2·116=R216∴ R=4h1h2
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