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A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two times of flight is proportional to

a
R
b
1/R
c
1/R2
d
R2

detailed solution

Correct option is A

Here t1=2usin⁡αg and t2=2usin⁡90∘−αg…(1)Now    t1t2=4u2g2sin⁡αcos⁡αWe know thatR=u2sin⁡2αgFrom eqs. (1) and (2), we get t1t2=2Rg∝R

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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