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Q.

A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two times of flight is proportional to

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a

R

b

1/R

c

1/R2

d

R2

answer is A.

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Detailed Solution

Here t1=2usin⁡αg and t2=2usin⁡90∘−αg…(1)Now    t1t2=4u2g2sin⁡αcos⁡αWe know thatR=u2sin⁡2αgFrom eqs. (1) and (2), we get t1t2=2Rg∝R
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