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A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flight in the two cases, then what is the product of two times of flight?

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a
t1t2∝R2
b
t1t2∝R
c
t1t2∝1R
d
t1t2∝1R2

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detailed solution

Correct option is B

The horizontal range is the same for the angles of projection θ and90∘−θt1=2usin⁡θgt2=2usin⁡90∘−θg=2ucos⁡θgt1t2=2usin⁡θg×2ucos⁡θg=2gu2sin⁡2θg=2gR where  R=u2sin⁡2θg Hence,  t1t2∝R.


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