A projectile can have same range R for two angles of projection. It t1 and t2 are the times of flight in the two cases, then what is the product of two times of flight?
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a
t1t2∝R2
b
t1t2∝R
c
t1t2∝1R
d
t1t2∝1R2
answer is B.
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Detailed Solution
The horizontal range is the same for the angles of projection 90∘−θt1=2usinθg,t2=2usin90∘−θg=2ucosθg t1t2=2usinθg×2ucosθg=2gu2sin2θg=2gR where R=u2sin2θ Hence, t1t2∝R (as R isconstant)