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A projectile can have same range R for two angles of projection. It t1 and t2 are the times of flight in the two cases, then what is the product of two times of flight?
 

a
t1t2∝R2
b
t1t2∝R
c
t1t2∝1R
d
t1t2∝1R2

detailed solution

Correct option is B

The horizontal range is the same for the angles of projection 90∘−θt1=2usin⁡θg,t2=2usin⁡90∘−θg=2ucos⁡θg t1t2=2usin⁡θg×2ucos⁡θg=2gu2sin⁡2θg=2gR  where R=u2sin⁡2θ   Hence, t1t2∝R        (as R isconstant)

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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