Q.

A projectile can have same range R for two angles of projection. It t1 and t2 are the times of flight in the two cases, then what is the product of two times of flight?

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a

t1t2∝R2

b

t1t2∝R

c

t1t2∝1R

d

t1t2∝1R2

answer is B.

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Detailed Solution

The horizontal range is the same for the angles of projection 90∘−θt1=2usin⁡θg,t2=2usin⁡90∘−θg=2ucos⁡θg t1t2=2usin⁡θg×2ucos⁡θg=2gu2sin⁡2θg=2gR  where R=u2sin⁡2θ   Hence, t1t2∝R        (as R isconstant)
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