Q.
A projectile is fired at an angle 300 to the horizontal such that the vertical component of the initial velocity is 80 m/s. Find approximately the velocity of the projectile at time T4 where T is time of flight.
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a
180 m/s
b
155 m/s
c
145 m/s
d
140 m/s
answer is C.
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Detailed Solution
u sin 300 = 80 ⇒u = 160 m/sux = u cos300 = 160 32 = 803 m/sT = 2usin300g = 2×8010 = 16 svy = uy-gT4 = 80-10×164 = 40 m/sv = vx2+vy2 = (803)2+402 = 145 m/s
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