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Q.

A projectile is fired at an angle 300 to the horizontal such that the vertical component of the initial velocity is 80 m/s. Find approximately the velocity of the projectile at time T4 where T is time of flight.

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a

180 m/s

b

155 m/s

c

145 m/s

d

140 m/s

answer is C.

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Detailed Solution

u sin 300 = 80 ⇒u = 160 m/sux = u cos300 = 160 32 = 803 m/sT = 2usin300g = 2×8010 = 16 svy = uy-gT4 = 80-10×164 = 40 m/sv = vx2+vy2 = (803)2+402 = 145 m/s
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