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A projectile is fired at an angle of  30o to the horizontal such that the vertical component of initial velocity is 80m/s.  its time of fight is T. Its velocity at  t=T/4 has a magnitude of nearly

a
200m/s
b
300m/s
c
140m/s
d
100m/s

detailed solution

Correct option is C

given angle of projection =θ=300; vertical component of initial velocity =uy=80 m/s;we know,      uxuy=cot⁡30∘ux80=3ux=803m/ stime of flight= T=2uyg=2×8010∴T=16s At t=T4=4s,ux=vx=803m/svy=uy-gt    substitute obtained values,vy=80−10×4=40m/sv=vx2+vy2∴v=(803)2+(40)2≈144m/s

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