Questions
A projectile is fired at an angle of to the horizontal such that the vertical component of initial velocity is its time of fight is T. Its velocity at has a magnitude of nearly
detailed solution
Correct option is C
given angle of projection =θ=300; vertical component of initial velocity =uy=80 m/s;we know, uxuy=cot30∘ux80=3ux=803m/ stime of flight= T=2uyg=2×8010∴T=16s At t=T4=4s,ux=vx=803m/svy=uy-gt substitute obtained values,vy=80−10×4=40m/sv=vx2+vy2∴v=(803)2+(40)2≈144m/sTalk to our academic expert!
Similar Questions
The equation of trajectory of projectile is given by where x and y are in metre. The maximum range of the projectile is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests